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50x-x^2=624
We move all terms to the left:
50x-x^2-(624)=0
We add all the numbers together, and all the variables
-1x^2+50x-624=0
a = -1; b = 50; c = -624;
Δ = b2-4ac
Δ = 502-4·(-1)·(-624)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2}{2*-1}=\frac{-52}{-2} =+26 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2}{2*-1}=\frac{-48}{-2} =+24 $
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